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SOLVED: Scanner input - new Scanner(System.in; int vl -input.nextInt(); int v2 = input.nextInt(); 5tring line = input.nextLine(); Select one: After the last statement is executed, v1 is 34 The program has a
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![Java scanner.nextLine() Method Call Gets Skipped Error [SOLVED]](https://www.freecodecamp.org/news/content/images/2022/08/java-scanner-nextline-call-gets-skipped-solved.jpg "Java scanner.nextLine() Method Call Gets Skipped Error [SOLVED]")
Java scanner.nextLine() Method Call Gets Skipped Error [SOLVED]
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Solved You are using a Scanner in a Java program to collect | Chegg.com
I dont understand java scanner, im doing this course, I dont understand the .nextLine() , next() , nextInt() . I searched it but didnt understand any of it, can someone please explain ?
Java Input
java.util.scanner - Java - Scanner - Skips over my last nextLine() request - Stack Overflow
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